看代碼：
復(fù)制代碼 代碼如下:
set statistics io on
set statistics time on
go
set statistics profile on
go
use pubs
select * from authors
where (au_fname like 'S%' or au_fname like 'a%')
and (state like 'CA' or state like 'UT')
and (cast(zip as int) > 90000)
select * from authors
where (au_fname like 'S%' or au_fname like 'a%')
and (cast(zip as int) > 90000)
and (state like 'CA' or state like 'UT')
select * from authors
where (cast(zip as int) > 90000)
and (au_fname like 'S%' or au_fname like 'a%')
and (state like 'CA' or state like 'UT')
目的：想驗(yàn)證where語句的各個條件的查詢順序
環(huán)境：SQLServer 2005Express版本
步驟：顯示查詢計劃
結(jié)果：無一例外，都被統(tǒng)一成了這樣的代碼
復(fù)制代碼 代碼如下:
|--Clustered Index Scan(OBJECT:([pubs].[dbo].[authors].[UPKCL_auidind]), WHERE:(CONVERT(int,[pubs].[dbo].[authors].[zip],0)>(90000) AND ([pubs].[dbo].[authors].[au_fname] like 'S%' OR [pubs].[dbo].[authors].[au_fname] like 'a%') AND ([pubs].[dbo].[authors].[state] like 'CA' OR [pubs].[dbo].[authors].[state] like 'UT')))
結(jié)論：貌似在2005之前的版本中，where子句的順序是從前往后的。但是又貌似在2005的版本中進(jìn)行了優(yōu)化，所有的順序都被統(tǒng)一成了以過濾能力進(jìn)行排序的語句。
